![Why did we choose n+1 in this proof of pumping lemma for context free language? I can't understand what are we trying to show by choosing i=n+1 | Free Math Help Forum Why did we choose n+1 in this proof of pumping lemma for context free language? I can't understand what are we trying to show by choosing i=n+1 | Free Math Help Forum](https://www.freemathhelp.com/forum/data/attachments/27/27021-4f36241f339d2796d6ce41cfd93099a5.jpg)
Why did we choose n+1 in this proof of pumping lemma for context free language? I can't understand what are we trying to show by choosing i=n+1 | Free Math Help Forum
![SOLVED: Q10: (10 points) Use the pumping lemma to show that the following language is not regular: A = a*b'/n > 0 (15 points) Use the pumping lemma to show that the SOLVED: Q10: (10 points) Use the pumping lemma to show that the following language is not regular: A = a*b'/n > 0 (15 points) Use the pumping lemma to show that the](https://cdn.numerade.com/ask_images/cf9a1b0eaf6e428d9d768fbf106057a4.jpg)
SOLVED: Q10: (10 points) Use the pumping lemma to show that the following language is not regular: A = a*b'/n > 0 (15 points) Use the pumping lemma to show that the
![PPT - Background Information for the Pumping Lemma for Context-Free Languages PowerPoint Presentation - ID:9724023 PPT - Background Information for the Pumping Lemma for Context-Free Languages PowerPoint Presentation - ID:9724023](https://image5.slideserve.com/9724023/pumping-lemma-for-context-free-languages-l.jpg)
PPT - Background Information for the Pumping Lemma for Context-Free Languages PowerPoint Presentation - ID:9724023
![Homework #7 Solutions. #1. Use the pumping lemma for CFL's to show L = {a i b j a i b j | i, j > 0} is not a CFL. Proof by contradiction using the Pumping. - ppt download Homework #7 Solutions. #1. Use the pumping lemma for CFL's to show L = {a i b j a i b j | i, j > 0} is not a CFL. Proof by contradiction using the Pumping. - ppt download](https://images.slideplayer.com/17/5311175/slides/slide_2.jpg)
Homework #7 Solutions. #1. Use the pumping lemma for CFL's to show L = {a i b j a i b j | i, j > 0} is not a CFL. Proof by contradiction using the Pumping. - ppt download
![Context Free Grammars 1. Context Free Languages (CFL) The pumping lemma showed there are languages that are not regular –There are many classes “larger” - ppt download Context Free Grammars 1. Context Free Languages (CFL) The pumping lemma showed there are languages that are not regular –There are many classes “larger” - ppt download](https://images.slideplayer.com/27/8928280/slides/slide_2.jpg)
Context Free Grammars 1. Context Free Languages (CFL) The pumping lemma showed there are languages that are not regular –There are many classes “larger” - ppt download
![PPT - Background Information for the Pumping Lemma for Context-Free Languages PowerPoint Presentation - ID:3925259 PPT - Background Information for the Pumping Lemma for Context-Free Languages PowerPoint Presentation - ID:3925259](https://image2.slideserve.com/3925259/background-information-for-the-pumping-lemma-for-context-free-languages-l.jpg)
PPT - Background Information for the Pumping Lemma for Context-Free Languages PowerPoint Presentation - ID:3925259
![PPT - Use the pumping theorem for context-free languages to prove that PowerPoint Presentation - ID:6033349 PPT - Use the pumping theorem for context-free languages to prove that PowerPoint Presentation - ID:6033349](https://image3.slideserve.com/6033349/slide1-n.jpg)